已知函式f(x)=3x,且f-1(18)=a+2,g(x)=3ax-4x的定義域為[0,1].(1)求g(x)...
![已知函式f(x)=3x,且f-1(18)=a+2,g(x)=3ax-4x的定義域為[0,1].(1)求g(x)...](https://i2.guowenba.com/2a3f740786fedf90c5/2b2f7f1c/756e2b/736b284bd7afca97d744-s.gif "已知函式f(x)=3x,且f-1(18)=a+2,g(x)=3ax-4x的定義域為[0,1].(1)求g(x)...")
問題詳情：已知函式f(x)=3x,且f-1(18)=a+2,g(x)=3ax-4x的定義域為[0,1].(1)求g(x)的解析式;(2)求g(x)的值域.【回答】解(1)因為f(x)=3x,所以f-1(x)=log3x,f-1(18)=log318=2+log32,所以a=log32.所以g(x)=-4x=2x-4x,所以g...
問題詳情：已知函式f(x)=3x,且f-1(18)=a+2,g(x)=3ax-4x的定義域為[0,1].(1)求g(x)的解析式;(2)求g(x)的值域.【回答】解(1)因為f(x)=3x,所以f-1(x)=log3x,f-1(18)=log318=2+log32,所以a=log32.所以g(x)=-4x=2x-4x,所以g...