問題詳情：
某公司需招聘一名員工，對應聘者*、乙、*從筆試、面試、體能三個方面進行量化考核，*、乙、*各項得分如下表：
筆試 | 面試 | 體能 | |
* | 83 | 79 | 90 |
乙 | 85 | 80 | 75 |
* | 80 | 90 | 73 |
(1)根據三項得分的平均分，從高到低確定三名應聘者的排名順序．
(2)該公司規定：筆試，面試、體能得分分別不得低於80分，80分，70分，並按60%，30%，10%的比例計入總分，根據規定，請你說明誰將被錄用．
【回答】
解：(1)
=（83+79+90）÷3=84，
=（85+80+75）÷3=80，
=（80+90+73）÷3=81．············································································ 3分
從高到低確定三名應聘者的排名順序為：*，*，乙；··································· 4分
(2)∵該公司規定：筆試，面試、體能得分分別不得低於80分，80分，70分，
∴*淘汰，···································································································· 5分
乙成績=85×60%+80×30%+75×10%=82.5，······················································· 7分
*成績=80×60%+90×30%+73×10%=82.3，····················································· 9分
∴乙將被錄取． ························································································· 10分
知識點：資料的波動程度
題型：解答題
