SBD造句
ApplicationofIridiumSBDDataCommunicationUnitinSpecialRegionGamma-rayradiationeffectonNi/4H-SiCSBDThedefencemodelofbackfielderbasedonSBDstrategyasactivedefenceactioncanbeappliedeasilyafterthebackfielde...
ApplicationofIridiumSBDDataCommunicationUnitinSpecialRegionGamma-rayradiationeffectonNi/4H-SiCSBDThedefencemodelofbackfielderbasedonSBDstrategyasactivedefenceactioncanbeappliedeasilyafterthebackfielde...
问题详情:如图,直角梯形ABDC中,AB∥CD,AB>CD,S是直角梯形ABDC所在平面外一点,画出平面SBD和平面SAC的交线,并说明理由.【回答】解很明显,点S是平面SBD和平面SAC的一个公共点,即点S在交线上,由于AB>CD,则分别延长AC和BD交于点E,如图...