已知*P={(x,y)|x+y=a},Q={(x,y)|2x-3y=b},若P∩Q={(4,-2)},则a=...
问题详情：已知*P={(x,y)|x+y=a},Q={(x,y)|2x-3y=b},若P∩Q={(4,-2)},则a=,b=. 【回答】214解析因为P∩Q={(4,-2)},所以(4,-2)∈P,(4,-2)∈Q,所以4+(-2)=a,且2×4-3×(-2)=b,解得a=2,b=14.知识点：*与函数的概念题型：填空...
问题详情：已知*P={(x,y)|x+y=a},Q={(x,y)|2x-3y=b},若P∩Q={(4,-2)},则a=,b=. 【回答】214解析因为P∩Q={(4,-2)},所以(4,-2)∈P,(4,-2)∈Q,所以4+(-2)=a,且2×4-3×(-2)=b,解得a=2,b=14.知识点：*与函数的概念题型：填空...